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2 August, 00:27

if log 2 = a, log 3 = b, and log 7 = c what is log 490 in terms of a, b and c and you can have integer coefficients

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  1. 2 August, 01:12
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    Answer is 2*c + log [10^{a} + 10^{b}] + a

    Step-by-step explanation:

    log 2 = a, log 3 = b, log 7 = c

    Using formula

    log d*e = log d + log e

    log d^{a} = a*log d

    log 5 = log [10^{a} + 10^{b}]

    log 490 in terms of a, b and c and you can have integer coefficients

    log 490

    = log 7^{2}*5*2

    = 2*log 7 + log 5 + log 2

    = 2*c + log [10^{a} + 10^{b}] + a

    Answer is 2*c + log [10^{a} + 10^{b}] + a
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