Ask Question
7 December, 02:44

What is the growth factor of y=34*4^x, the initial amount of y=15*3^x and the decay factor of y=17*0.2^x

+4
Answers (1)
  1. 7 December, 03:24
    0
    So the growth factor is the base of the exponential term, so the base of y = 34 * 4^x is 4.

    the initial amount is the amount at x = 0

    y = 15 * 3^xy = 15 * 3^0y = 15 * 1y = 15 is the initial amount

    the decay factor of y=17*0.2^x is same as the growth factor, it is 0.2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the growth factor of y=34*4^x, the initial amount of y=15*3^x and the decay factor of y=17*0.2^x ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers