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11 November, 09:41

Complete the definition of the h (x) so that it is continuous over its domain.

h (x) = x^3, x<0

a, x=0

√x, 0 b, x=4

4 - 1/2x, x>4

a = b =

+2
Answers (1)
  1. 11 November, 11:52
    0
    A=0

    B=2

    so we have our question, h (x) x^3, x<0.

    a is equal to 0 since that answer was already given.

    so now it would be srqt/x over 0 of 4

    4 divided by 0 is 0

    1/2x x>4

    turns into 1/2x x>4/1

    cross simplify

    the answer to B is 2
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