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4 February, 13:57

The critical angle of refraction for calcite is 68.4 when it forms a boundary with water. Use this information to determine the speed of light in Calcite. Assume the refractive index of water, 1.333, is less than the refractive index of calcite.

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  1. 4 February, 14:59
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    Using Snell's law with

    N2=1.33 for water

    N1 sin A1 = N2 sin A2 = N2

    N1 = 1.33/sinA

    so, the speed of light in clctie = (3*10^8 m/s) / 1.43

    = 1*10^8 m/s
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