3. How many solutions does the system have? }

Sy = x2 + 4x - 2

1 y = 2x+1

Hence two solution of expression

I. e x = 1, - 3

Step-by-step explanation:

Given as:

y = x² + 4 x - 2

And y = 2 x + 1

Solving these equation

x² + 4 x - 2 = 2 x + 1

or, x² + 4 x - 2 - 2 x - 1 = 0

Or, x² + 2 x - 3 = 0

Or, x² + 3 x - x - 3 = 0

Or, x (x + 3) - 1 (x + 3) = 0

Or, (x + 3) (x - 1) = 0

or, x = - 3 And x = 1

Hence two solution of expression Answer