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28 January, 22:45

What are the zeros of the quadratic function f (x) = 2x^2+8x-3

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  1. 29 January, 01:30
    0
    -2 + / - [ (sqrt 88) / 4]

    or

    0.35, - 4.35 to the nearest hundredth.

    Step-by-step explanation:

    2x^2 + 8x - 3 = 0

    Using the quadratic formula:

    x = [ - 8 + / - sqrt (8^2 - 4*2*-3) ] / 4

    = - 2 + / - (sqrt 88) / 4
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