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1 February, 14:14

Solve for x. Enter your answer in interval notation using grouping symbols x^2+2x<15

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  1. 1 February, 17:28
    0
    The answer to your question is (-5, 3)

    Step-by-step explanation:

    Process

    1. - Factor the inequality

    x² + 2x < 15

    x² + 2x - 15 < 0

    (x + 5) (x - 3) < 0

    2. - Find x,

    - the inequality must be negative, so x + 5 0

    x + 5 0

    x 3 the solutions do not crosses

    - the inequality must be negative, so x + 5 > 0 and x - 3 < 0

    x > - 5 x < 3

    The solutions crosses in the interval (-5, 3) so this is the solution
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