Bottle A contains 4 ounces of water, which is 25% of the amount of water in Bottle B. How much water is there in Bottle B?

Bottle C contains 150% of the water in Bottle B. How much water is there in Bottle C?

Bottle D contains 12 ounces of water. What percentage of the amount of water in Bottle B is this?

Question

Mathematics

Guest

19 January, 01:27

Bottle A contains 4 ounces of water, which is 25% of the amount of water in Bottle B. How much water is there in Bottle B?

Bottle C contains 150% of the water in Bottle B. How much water is there in Bottle C?

Bottle D contains 12 ounces of water. What percentage of the amount of water in Bottle B is this?

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Answers (1)

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Aubrey · Answer 1

B=16 ounces

C=24 ounces

B=1/0.75=133%

Step-by-step explanation:

we have that

A≡0.25B (25%), if A=4 ounces then B=4/0.25 = 16 ounces

C=1.5B (150%), if B=16 ounces then C=1.5 * (16 ounces) = 24 ounces

D≡xB (?%), if D=12 ounces then x=12/16 = 0.75 ≡ 75%, but xB≡D ⇒ B≡D/x →

B≡12 (1/0.75) = B=12 * (1.333) → B≅133%D