Find the angle between the given vectors to the nearest tenth of a degree.

u =, v =

-8.3°

1.7°

3.3°

13.3°

Step-by-step explanation:

If θ is the angle between two vectors u and v, then cosθ = (u·v) / [llull llvll]

u·v = (8) (9) + (7) (7) = 121

llull = √[ (8) 2 + (9) 2] = √145 llvll = √[ (7) 2 + (7) 2] = 7√2

So, cosθ = 121 / [7√290]

= 1.015052094

θ = Cos-1 (1.015052094) ≈ 3.3