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26 August, 07:11

For the equation 3 (2x - 5) = 6x + k, which value of k will create an equation with infinitely many solutions? A 5

B - 5

C 15

D - 15

+5
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  1. 26 August, 10:13
    0
    3 (2x-5) = 6x+k

    6x-15=6x+k

    6x-6x=k+15

    0=k+15

    k=-15
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