What are possible solutions to 2x+y=-12

x = 0 and y = - 12x = - 6 and y = 0x = 2 and y = - 16

Step-by-step explanation:

Convert to the slope-intercept form:

y = mx + b

2x + y = - 12 subtract 2x from both sides

y = - 2x - 12

1. Take any value of x.

2. Put it to the equation.

3. Calculate the value of y.

Examples:

for x = 0

y = - 2 (0) - 12 = 0 - 12 = - 12

for x = - 6

y = - 2 (-6) - 12 = 12 - 12 = 0

for x = 2

y = - 2 (2) - 12 = - 4 - 12 = - 16

...

x = 5

y=2

2*5+2=12

2*2+8

or

2*1+10