Complete the do-while loop to output 0 to the value of countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the expected output will be

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Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the expected output will be 0 1 2 3 4 5

import java. util. Scanner;

public class CountToLimit {

public static void main (String [] args) {

Scanner scnr = new Scanner (System. in);

int countLimit = 0;

int printVal = 0;

/ / Get user input

countLimit = scnr. nextInt ();

printVal = 0;

do {

System. out. print (printVal + " ");

printVal = printVal + 1;

} while ( / * Your solution goes here * / );

System. out. println ("");

return;

}

}

Answer:

Replace while ( / * Your solution goes here * / );

With

while (printVal < = countLimit);

This will check if the value of variable printVal is still within print range of variable countLimit.

The full program becomes

import java. util. Scanner;

public class CountToLimit {

public static void main (String [] args) {

Scanner scnr = new Scanner (System. in);

int countLimit = 0;

int printVal = 0;

/ / Get user input

countLimit = scnr. nextInt ();

printVal = 0;

do {

System. out. print (printVal + " ");

printVal = printVal + 1;

} while (printVal < = countLimit);

System. out. println ("");

return;

}

}