The sum of three numbers is 112. The second number is 4 times the third. The first number is 8 less that the third. What are the numbers?

First number (x) = 12

Second number (y) = 80

Third number (z) = 20

Step-by-step explanation:

Let assume x, y, z to represent first, second and third respectively.

X + y + z = 112

Y = 4z

X = z - 8

So therefore

(Z-8) + (4z) + z = 112

Z + 4z + z = 112 + 8

6z = 120

Z = 120/6

Z = 20.

So,

First x = z - 8

20 - 8 = 12

Second y = 4z

4 x 20 = 80

Third z = 20