The height in feet of a skydiver t seconds after deploying her parachute is given by h (t) = - 300t + 1000. A ball is thrown up toward the skydiver, and after t seconds, the height of the ball in feet is given by h (t) = - 16t2 + 100t. When does the ball reach the skydiver?

Question

Mathematics

Blaine

29 May, 10:20

The height in feet of a skydiver t seconds after deploying her parachute is given by h (t) = - 300t + 1000. A ball is thrown up toward the skydiver, and after t seconds, the height of the ball in feet is given by h (t) = - 16t2 + 100t. When does the ball reach the skydiver?

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Answers (1)

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Tiffany Chapman · Answer 1

The ball reaches skydiver at 2.81 seconds.

Step-by-step explanation:

Height of sky diver

h (t) = - 300t + 1000

Height of ball

h (t) = - 16t² + 100t

We need to find when does the ball reach the skydiver

That is both heights are equal

-300t + 1000 = - 16t² + 100t

16t² - 400t + 1000 = 0

t = 22.18 s or t = 2.81 s

The ball reaches skydiver at 2.81 seconds.