Two pumps are used to empty a sewage tank. One pump pumps 60 gallons per minute (gpm) and the second pumps 50 gpm. They pumped for 30 minutes. How many total gallons are pumped?

Total gallons of sewage water pumped is 3300 gallons

Solution:

Given that One pump pumps 60 gallons per minute

The second pumps 50 gallons per minute

To find: total gallons pumped

Total time taken by both the pumps to empty tank = 30 minutes

Rate of pumping the tank by first pump = x = 60 gallons per minute

Rate of pumping the tank by second pump = y = 50 gallons per minute

From given question,

total rate of pumping the sewage tank with first and second pump = x + y

x + y = 60 + 50 = 110 gallons per minute

They together pumped 110 gallons per minute

Given that they pumped for 30 minutes

So for 30 minutes, total gallons pumped is given as:

⇒ 110 x 30 = 3300 gallons

Therefore, total gallons of sewage water pumped is 3300 gallons