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27 June, 07:38

Use the complete square to solve the problem.

1. t^2-5x+6=0

2. 2x^2-8x-3=0

3. w^2+4w-6=0

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Answers (1)
  1. 27 June, 10:08
    0
    1. t² - 5x + 6 = 0

    x = - (-5) + / - √ (-5) ² - 4 (1) (6)

    2 (1)

    x = 5 + / - √25 - 24

    2

    x = 5 + / - √1

    2

    x = 5 + / - 1

    2

    x = 5 + 1 x = 5 - 1

    2 2

    x = 6 x = 4

    2 2

    x = 3 x = 2

    2. 2x² - 8x - 3 = 0

    x = - (-8) + / - √ (-8) ² - 4 (2) (-3)

    2 (2)

    x = 8 + / - √64 + 24

    4

    x = 8 + / - √88

    4

    x = 8 + / - 9.38083152

    4

    x = 8 + 9.38083152 x = 8 - 9.38083152

    4 4

    x = 17.38083152 x = - 1.38083152

    4 4

    x = 4.34520788 x = - 0.34520788

    3. w² + 4w - 6 = 0

    x = - 4 + / - √4² - 4 (1) (-6)

    2 (1)

    x = - 4 + / - √16 + 24

    2

    x = - 4 + / - √40

    2

    x = - 4 + / - 6.32455532

    2

    x = - 4 + 6.32455532 x = - 4 - 6.32455532

    2 2

    x = 2.32455532 x = - 10.32455532

    2 2

    x = 1.16227766 x = - 5.16227766
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