Find the solutions to y = (x - 1) 2 for x = - 3, 0, and 3. (-3, - 2), (0, 1), (3, 4) (-3, - 16), (0, 1), (3, 4) (-3, 16), (0, 1), (3, 4) (-3, - 4), (0, - 1), (3, 2)

The pairs of (x, y) are (-3,16), (0,1) and (3,4)

Step-by-step explanation:

y = (x - 1) ²

y = x² - 2 x + 1

for x = - 3

y = (-3) ² - 2 * - 3 + 1

= 9 + 6 + 1

= 16

so (x, y) = (-3, 16)

for x = 0

y = 0² - 2 * 0 + 1

= 1

so (x, y) = (0,1)

For x = 3

y = 3² - 2 * 3 + 1

= 9 - 6 + 1

= 4

(x, y) = (3, 4)

so the pairs of (x, y) are (-3,16), (0,1) and (3,4)