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23 June, 19:47

Calculate the rate of change for the quadratic function over the given interval: f/left (x / right) = {x^2} + 4x + 5; /; - 1 / le x / le 2f (x) = x 2 + 4x+5; -1≤x≤2 1 5 2 - 4

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  1. 23 June, 22:01
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    Answer: The rate of change is 5.

    Step-by-step explanation:

    Our equation is:

    f (x) = x^2 + 4x + 5

    And we want to find the rate of change in the range - 1≤ x ≤2

    when we want to find the rate between x1 ≤ x ≤ x2

    we have:

    Rate = (f (x2) - f (x1)) / (x2 - x1)

    So we have:

    Rate = (f (2) - f (-1)) / (2 - 1)

    Rate = (2^2 + 4*2 + 5 - (-1) ^2 - 4 * (-1) - 5) / 3 = 15/3 = 5

    The rate of change is 5.
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