You roll a six-sided die twice. What is the probability of rolling a 3 and then a 5? A) 1 3 B) 1 6 C) 1 12 D) 1 36

Answer: 1/36

Step-by-step explanation: In this problem, we're given that a number cube is rolled twice and we're asked to find the probability of rolling a 3 and a 5.

It's important to understand that the 2 rolls of the number cube are independent events because the result of 1 roll does not affect the result of the other roll.

To find the probability of two independent events, we first find the probability of each event, then we multiply the probabilities.

So let's first find the probability of rolling a 3 with our first role of the number cube. We can find the probability of an event using the ratio below.

Number of favorable outcomes/total number of outcomes

Since there is only one way to roll a 3 and there are six possible outcomes 1, 2, 3, 4, 5, and 6, the probability of rolling a 3 is 1/6.

Next, we find the probability of rolling a 5 with our second role of the number cube which would also be 1/6 because each side is as likely to come up as another number.

Now, to find the probability of rolling a 3 and a 5, we simply multiply the probabilities. Multiplying across the numerators, 1 · 1 is 1 and multiplying across the denominators, 6 · 6 is 36.

This means the probability of rolling a 3 and then a 5 is 1/36.