Factored completely, the expression 2xexponent2 + 10x - 12 is equivalent to

2 (x - 6) (x + 1)

2 (x + 6) (x - 1)

2 (x + 2) (x + 3)

2 (x - 2) (x - 3)

Question

Mathematics

Dalton

8 April, 16:45

Factored completely, the expression 2xexponent2 + 10x - 12 is equivalent to

2 (x - 6) (x + 1)

2 (x + 6) (x - 1)

2 (x + 2) (x + 3)

2 (x - 2) (x - 3)

+1

Answers (2)

Know the Answer?

Harper Lyons · Answer 1

2 (x + 6) (x - 1)

Step-by-step explanation:

2x² + 10x - 12

2[x² + 5x - 6]

2[x² + 6x - x - 6]

2[x (x + 6) - (x + 6) ]

2 (x + 6) (x - 1)

Christina · Answer 2

2 (x+6) (x-1)

Step-by-step explanation:

2x^2 + 10x - 12

Factor out a 2

2 (x^2 + 5x-6)

What 2 numbers multiply to - 6 and add to 5

6*-1 = - 6

6+-1 = 5

2 (x+6) (x-1)

Factored completely, the expression 2xexponent2 + 10x - 12 is equivalent to2 (x - 6) (x + 1)2 (x + 6) (x - 1)2 (x + 2) (x + 3)2 (x - 2) (x - 3)

Factored completely, the expression 2xexponent2 + 10x - 12 is equivalent to

2 (x - 6) (x + 1)

2 (x + 6) (x - 1)

2 (x + 2) (x + 3)

2 (x - 2) (x - 3)