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4 October, 11:49

How do you solve (2x-7) (5x+3) = 0

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  1. 4 October, 13:12
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    Step-by-step explanation:

    First I do it as separate equations 2x-7=0 and 5x+3=0. In this equation you get two answers so you first answer 2x-7=0

    2x-7=0

    +7 + 7

    2x=7

    /2 / 2

    x=7/2

    Then do 5x+3=0

    -3 - 3

    5x=-3

    /5 / 5

    x = - 3/5

    Then you can check by putting them back in.
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