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31 May, 08:28

Boris chooses three different numbers the sum of the three numbers is 36 one of the numbers is a cube number the other two numbers are factors of 20 find three numbers chosen by boris. write the numbers in ascending order

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  1. 31 May, 12:09
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    3,4,5

    Step-by-step explanation:

    Here, we need to asume that the values are integers, as if not, there will be infinite solutions.

    Lets go by parts:

    The 1st number is a cubic, lets call it A

    The second is a factor of 20, lets call it B. The same for the 3rd, call it C.

    So, A + B + C = 36

    There are no many factors of 20, those are the numbers that when multiplied gives as the value of 20. Those are 1, 2, 4, 5, 10 and 20. So, B and C are some of these numbers.

    Then, we know A if less than 36, other way the whole sum will be greater than 36. How many cubic number with integer cubic roots are less than 36? Well, lets guess:

    1^3 = 1 - > valid, as it is less than 36

    2^3 = 8 - > valid, as it is less than 36

    3^2 = 27 - > valid, less than 36

    4^3 = 64 - > not valid, as it is greater than 36

    So, A ir 1, 2 or 3.

    If A is 1, then B+C needs to be 35. But, from the factors of 20 that we listed, there are no combinations of 2 numbers that sum 35. So, A CAN'T be 1.

    If A = 2, then we have:

    8 + B + C = 36

    B + C = 28

    And again, there are not combinations of two factors of 20 that sum 28 (try yourself).

    If A=3:

    27 + B + C = 36

    B + C = 9

    And we have a winner! If B=4 and C=5 (or viceversa C=4 and B=5)

    27 + 4 + 5 = 36

    So, A=3, B=4 and C=5 or A=3, C=4 and B=5 are solutions.
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