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27 September, 02:52

In a right triangle ABC A and B are complementary angles and sin A = 8/9 what is cos B

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  1. 27 September, 04:47
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    A^2 + b^2 = c^2

    8^2 + b^2 = 9^2

    64 + b^2 = 81

    b^2 = 17

    b = + / - sqrt (17) / 9

    cos B = b/c

    cos B = + / - sqrt (17) / 9
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