Ask Question
16 December, 12:21

Let f (x) = x^2-16 and g (x) = x+4. Find f/g and it's domain

+3
Answers (2)
  1. 16 December, 15:56
    0
    f/g = (x+4)

    Step-by-step explanation:

    f*g means multiply the functions.

    (x^2-16) (x-4) = x^3-4x^2-16x+64.

    f/g means divide the functions

    (x^2-16) / (x-4), but the numerator is a difference of squares, (x+4) (x-4), and the last cancels the denominator.

    f/g = (x+4)

    Domains of a composite function are the domains that satisfy both.

    f (x) has domain of all reals.

    g (x) does too.

    Their composite domain is all reals

    In the second, the denominator is (x-4).

    The function doesn't exist at x=4, regardless of what can be factored. Therefore,

    the domain of f/g is all reals except x=4.
  2. 16 December, 16:11
    0
    Step-by-step explanation:

    f (x) = x^2-16 and g (x) = x+4

    f/g = (x² - 16) / (x + 4)

    = (x + 4) (x - 4) / (x + 4)

    = x - 4
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Let f (x) = x^2-16 and g (x) = x+4. Find f/g and it's domain ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers