On the average, 1 1/3 bushels of seed are needed to plant 1 acre of wheat. How many bushels of seed would be required to plant 30 acres?

Answer:40 bushels of seed would be required to plant 30 acres of wheat.

Step-by-step explanation:

On the average, 1 1/3 bushels of seed are needed to plant 1 acre of wheat. Converting 1 1/3 bushels of seed to improper fraction, it becomes 4/3 bushels of seed.

Let x represent the bushels of seed that would be required to plant 30 acres. Therefore

4/3 bushels of seed = 1 acre

x = 30 acres

Cross multiplying

x * 1 = 4/3 * 30

x = 40 bushels of seed