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22 July, 17:37

With data from the 2009 National Health Interview Survey, the Centers for Disease Control estimated that 9.4% of U. S. children had asthma. Suppose that 12% of a random sample of 500 U. S. poor children have asthma.

We used the estimate from the 2009 National Health Interview Survey to calculate a standard error of 0.013. The data allows the use of a normal model. So we can find an approximate 95% confidence interval for the percentage of all U. S. poor children who have asthma.

Which interval is the approximate 95% confidence interval?

0.107 to 0.133

0.094 to 0.146

0.026 to 0.214

0.068 to 0.12

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  1. 22 July, 18:42
    0
    95% confidence interval is 0.094 to 0.146

    Step-by-step explanation:

    Confidence Interval can be calculated using p±ME where

    p is the sample mean of poor children who have asthma. (0.12 or 12%) ME is the margin of error from the mean

    And margin of error can be stated as ME=z*SE where

    z is the statistic of the 95% confidence level (1.96) SE is the standard error (0.013)

    Then ME=1.96*0.013≈0.0255

    Finally, 95% confidence interval is 0.12±0.0255 ≈ 0.094 to 0.146
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