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2 September, 18:54

Solve the following systems by substitution

question 1

x=5

2x+y=10

question 2

x++16y=20

x=4y

question 3

2x+8y=20

x=2

+4
Answers (1)
  1. 2 September, 22:03
    0
    The answer to your question is below

    Step-by-step explanation:

    Question 1

    x = 5 Equation l

    2x + y = 10 Equation ll

    - Substitute Equation l in equation ll

    2 (5) + y = 10

    y = 10 - 10

    y = 0

    - Solution (5, 0)

    Question 2

    x + 16y = 20 Equation l

    x = 4y Equation ll

    Substitute equation ll in equation l

    4y + 16y = 20

    20y = 20

    y = 20/20

    y = 1

    -Find x

    x = 4 (1)

    x = 4

    -Solution

    (4, 1)

    Question 3

    2x + 8y = 20 Equation l

    x = 2 Equation ll

    -Substitute equation ll in equation l

    2 (2) + 8y = 20

    4 + 8y = 20

    8y = 20 - 4

    8y = 16

    y = 16/8

    y = 2

    - Solution

    (2, 2)
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