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17 January, 22:41

How do i solve a quadratic equation like this

Solve.

3n2 = 147

A{-3, 7}

B{-7, 3}

C{-49, 49}

D{-7, 7}

+2
Answers (2)
  1. 17 January, 23:40
    0
    D{-7, 7}

    Dtep-by-step explanation:

    3n² = 147

    n² = 147/3

    n² = 49

    n = 7, - 7
  2. 18 January, 00:31
    0
    Option D. {-7, 7}

    Step-by-step explanation:

    3n^2 = 147

    First, divide both side 3

    n^2 = 147/3

    n^2 = 49

    Next, rearrange the variables to one side of the equation as shown below:

    n^2 - 49 = 0

    n^2 - 7^2 = 0

    The above is now difference of two squares. This can be solve by doing the following:

    (n - 7) (n + 7) = 0

    n - 7 = 0 or n + 7 = 0

    n = 7 or n = - 7
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