Two numbers have a sum of 21, and 3

times the first number minus the second

number is equal to 43. What are the two

numbers?

Step-by-step explanation: let the first number be x and the second number be y

according to the condition given

x+y=21

3x-y=43

using elimination method

3x+3y=63

3x-y=43

subtacting both the equations

4y=20

y=20/4

y=5

substituting value of y in eq 1

x+5=21

x=21-5

x=16

therefore x=16 and y=5

the two numbers are 16 and 5