Ask Question
17 October, 19:57

Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be modeled by (x-2) ^2=10 (y-3), where x and y are measured in inches. Where is the focus of the flashlight?

+2
Answers (1)
  1. 17 October, 20:27
    0
    F (2, 11/2)

    Step-by-step explanation:

    The expression:

    (x-2) ² = 10 (y - 3)

    can be rewritten in the vertex form as follows:

    (x-2) ² = 10y - 30

    (x-2) ² + 30 = 10y

    1/10 (x-2) ² + 3 = y

    General vertex form is:

    y = a (x-h) ² + k

    then, the vertex is locate at (h, k). In this case the vertes is (2, 3), and a = 1/10

    The focus of a parabola is located ar F (h, k+p), where p = 1 / (4a). Replacing into these equations:

    p = 1 / (4*1/10) = 5/2

    F (2, 3+5/2) = F (2, 11/2)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be modeled by (x-2) ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers