Find the solution of the square root of the quantity of x plus 3 plus 6 equals 9 and determine if it is an extraneous solution. (A. x=0 extraneous; B. x=0 non-extraneous; C. x=6 extraneous; D. x=6 non-extraneous)

√ (x+3) + 6=9

minus 6 both sides

√ (x+3) = 3

squar both sides

x+3=+/-9

minus 3 both sides

x=6 or - 12

sub to see

√ (6+3) + 6=9

√ (9) + 6=9

3+6=9

9=9

true

other one

√ (-12+9) + 6=9

√ (-9) + 6=9

false (means this is an extranious answer)

x=6 and it is not extranious

D

72 is anres