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17 April, 13:55

Express the following in the form

ax^2+bx+c=0:

(2x-1) (2x+1) = x (2x+3)

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  1. 17 April, 14:27
    0
    We want ax² + bx + c = 0

    So, lets go,

    (a + b). (a - b) = a² - b²

    (2x - 1). (2x + 1) = (2x) ² - 1² = 4x² - 1

    4x² - 1 = x. (2x + 3)

    4x² - 1 = 2x² + 3x

    4x² - 2x² - 1 - 3x = 0

    2x² - 3x - 1 = 0
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