Your research frm has found that salanies for coffee shop baristas have a normal distrbution with a mean of $16. 164 per year and a standard deviation of $1,459. Find the probability that a randomly selected barista has a salary greater than $13,000

a. 08461

b. 0.9582

c. 0.9850

d. 0.0150

e. 1.02

Answer: c. 0.9850

Step-by-step explanation:

Since the salaries for coffee shop baristas have a normal distrbution, we would apply the formula for normal distribution which is expressed as

z = (x - µ) / σ

Where

x = salaries for coffee shop baristas.

µ = mean salary

σ = standard deviation

From the information given,

µ = $16164

σ = $1459

We want to find the probability that a randomly selected barista has a salary greater than $13,000. It is expressed as

P (x > 13000) = 1 - P (x ≤ 1300)

For x = 1300,

z = (1300 - 16164) / 1459 = - 2.17

Looking at the normal distribution table, the probability corresponding to the z score is 0.015

P (x > 13000) = 1 - 0.015 = 0.985