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14 September, 10:33

Solve 4y^2-16y+16=0.

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Answers (2)
  1. 14 September, 10:46
    0
    y=2

    Step-by-step explanation:

    1) factor the equation

    2) set factors equal to 0
  2. 14 September, 11:14
    0
    Answer: y=2

    Step-by-step explanation:

    4y^2-16y+16=0 To "solve" means to find the value of x for which this equation is true.

    y^2 - 4y + 4 = 0 [divide by 4; this is the same equation]

    (y-2) (y-2) = 0 [You may factor or use the quadratic equation]

    y=2 and y=2 [the same answer]

    Check:

    Does (2) 2 - 4 (2) + 4 = 0?

    4 - 8 + 4 = 0?

    0 = 0? yes
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