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12 October, 21:19

Find the sample space for the experiment.

You toss a coin and a six-sided die.

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  1. 12 October, 21:29
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    For the first case we are going to assume that the order matters, on this case 6, H is not the same as H, 6

    The sampling space denoted by S and is given by:

    S = { (1, H), (2, H), (3, H), (4, H), (5, H), (6, H),

    (1, T), (2, T), (3, T), (4, T), (5, T), (6, T),

    (H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6),

    (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6) }

    If we consider that (5, H) is equal to (H, 5) "order no matter" then we will have just 12 elements in the sampling space:

    S = { (1, H), (2, H), (3, H), (4, H), (5, H), (6, H),

    (1, T), (2, T), (3, T), (4, T), (5, T), (6, T) }

    Step-by-step explanation:

    By definition the sample space of an experiment "is the set of all possible outcomes or results of that experiment".

    For the case described here: "Toss a coin and a six-sided die".

    Assuming that we have a six sided die with possible values {1,2,3,4,5,6}

    And for the coin we assume that the possible outcomes are {H, T}

    For the first case we are going to assume that the order matters, on this case 6, H is not the same as H, 6

    The sampling space denoted by S and is given by:

    S = { (1, H), (2, H), (3, H), (4, H), (5, H), (6, H),

    (1, T), (2, T), (3, T), (4, T), (5, T), (6, T),

    (H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6),

    (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6) }

    If we consider that (5, H) is equal to (H, 5) "order no matter" then we will have just 12 elements in the sampling space:

    S = { (1, H), (2, H), (3, H), (4, H), (5, H), (6, H),

    (1, T), (2, T), (3, T), (4, T), (5, T), (6, T) }
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