Question 1 What is - 12:2/3

Question 2 What is - 8/3:7/12

Question 3 Divide. 8.64: (-0.27)

Question 4 Starting at sea level, a submarine descended at a constant rate to a depth of - 3/4 mile relative to sea level in 5 minutes. What was the submarine's depth relative to sea level after the first minute?

Enter your answer in a fraction in simplest form.

Question 5 One cold night the temperature was 0 degrees at 8 p. m. The temperature dropped at a constant rate from 8 p. m. to midnight. At midnight the temperature was - 16.8 degrees.

What was the temperature at 9 p. m.?

Question

Mathematics

Everett Lawrence

28 September, 02:03

Question 1 What is - 12:2/3

Question 2 What is - 8/3:7/12

Question 3 Divide. 8.64: (-0.27)

Question 4 Starting at sea level, a submarine descended at a constant rate to a depth of - 3/4 mile relative to sea level in 5 minutes. What was the submarine's depth relative to sea level after the first minute?

Enter your answer in a fraction in simplest form.

Question 5 One cold night the temperature was 0 degrees at 8 p. m. The temperature dropped at a constant rate from 8 p. m. to midnight. At midnight the temperature was - 16.8 degrees.

What was the temperature at 9 p. m.?

+4

Answers (1)

Know the Answer?

Sharon Hines · Answer 1

Step-by-step explanation:

1) - 12:2/3 = - 12 * 3/2 = - 6*3 = - 18

2) - 8/3:7/12 = - 8/3 * 12/7 = - 8*12 / 3*7 = - 96/21

3) 8.64: (-0.27) = 8.64/-0.27 = 8.64*100/-0.27*100 = 864/-27 = - 32

4) The submarine's depth relative to sea level after the first minute = - 3/4 divided by 5

= - 3/4 * 1/5 = -3/20 = - 0.15 miles