Find the vertex.

x^2+16x+8

vertex: (-8,-56).

Question

Mathematics

Ty Dunn

28 May, 05:41

Find the vertex.

x^2+16x+8

vertex: (-8,-56).

+4

Answers (2)

Know the Answer?

Ashton Morris · Answer 1

The vertex is at (-8, - 56).

Step-by-step explanation:

x^2+16x+8

= (x + 8) ^2 - 64 + 8

= (x + 8) - 56.

The vertex is at (-8, - 56).

Zion Pena · Answer 2

Step-by-step explanation:

x² + 16x + 8

Complete the square. Take half of b, square it, then add and subtract.

(16/2) ² = 8² = 64

x² + 16x + 64 - 64 + 8

x² + 16x + 64 - 56

(x + 8) ² - 56

The vertex is (-8, - 56).

Find the vertex.x^2+16x+8vertex: (-8,-56).

Find the vertex.

x^2+16x+8

vertex: (-8,-56).