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4 December, 23:27

A number of miles driven this month was 30% decrease of the number of miles driven last month?

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Answers (2)
  1. 4 December, 23:50
    0
    70 miles driven this month

    Step-by-step explanation:

    This is an algebra problem and denote A number of miles driven this month as x to be found

    30 % decrease of x number of miles for this month last month miles driven = 100 % then 100 % / 100% * 100 miles = 100 miles thus this month = 100 % - 30 % = 70 % then for this month in miles = 70 % / 100 % * 100 miles = 70 miles
  2. 5 December, 02:38
    0
    70 miles were driven this month

    Step-by-step explanation:

    suppose 100 miles were driven last month

    30% = 30/100*100=30 miles

    30% decreasewould be 100-30 = 70 miles
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