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3 August, 23:00

Given that f (x) = 5x^3+ax^2-4x-2 and that (x-1) is a factor of f (x), find a.

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  1. A
    4 August, 01:51
    0
    a=1

    Step-by-step explanation:

    Because x-1 is factor of f (x)

    for x1=1, f (1) = 0, then

    f (1) = 5*1^3+a*1^2-4*1-2=0

    5*1+a*1-4-2=0

    5+a-6=0

    a-1=0

    a=1
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