The rectangle shown has a perimeter of 54 cm and the given area. It's length is 3 more than 5 times it's width. Write and some a system of equations to find the dimensions of the rectangle

Length = 23 cm

Width = 4 cm

Step-by-step explanation:

The area isn't given.

We will simply use the perimeter and length width information to find the dimensions of the rectangle.

Let length be x and width be y

Length is 3 more than 5 times width, so we can wriet:

x = 5y + 3

Also, the perimeter is the sum of all sides, so rectangle has 2 lengths and 2 widths, so perimeter is

P = 2x + 2y

and P = 54, so

54 = 2x + 2y

We know x = 5y + 3, so we substitute and find y:

54 = 2x + 2y

54 = 2 (5y + 3) + 2y

54 = 10y + 6 + 2y

48 = 12y

y = 48/12

y = 4

So, length (x) would be:

x = 5y + 3

x = 5 (4) + 3

x = 23

So, the dimensions of the rectangle is:

Length = 23 cm

Width = 4 cm