A sphere has a radius of 9 feet. A second sphere has a radius of 6 feet. What is the difference of the volumes of the spheres?

Difference of the volumes of the spheres=volume greater sphere - volume smaller sphere.

Volume of a sphere = (4/3) πr³

Difference of the volumes of the spheres = (4/3) πr₁³ - (4/3) πr₂³ = (4/3) π (r₁³-r₂³)

dа ta:

r₁=9 ft

r₂=6 ft

then:

Difference of the volumes of the spheres=4/3π[ (9 ft) ³ - (6 ft) ³] = (4/3) π (513 ft³) =

≈2148.85 ft³.

Answer: 2148.85 ft³

Well the formula to find the volume of a sphere is 3/4 (pi) r^3

sphere with the radius of 9: 3/4 (pi) 9^3 = 3053.63

sphere with the radius of 6: 3/4 (pi) 6^3 = 904.78

the difference: 2148.85