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21 February, 02:10

Find three positive consecutive integers such that the product of the smallest and the largest is 17 more than three times the median integer

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  1. 21 February, 02:38
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    There are two answers to this question

    the first possible answer is 5, 6, and 7 and the second possible answer is - 4, - 3, and - 2

    Step-by-step explanation:

    let the three numbers be (x-1), x, and (x+1)

    the product of the smallest and largest number is 17 more than 3 times the middle number, or

    (x-1) (x+1) = 3x+17, or

    x^2-1 = 3+17, or

    x^2-3x-18 = 0

    (x-6) (x+3) = 0

    So x = 6 or - 3

    Then just subtract one and add one to get the other integers. the three numbers are 5, 6, and 7 or - 4, - 3, and - 2
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