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18 June, 18:25

Which expression correctly shows 2x^5y-2x^2y factored completely over the integers?

A.-2x^2y (x+1) (x^2-x+1)

B. 2xy (x-1) (x^2+x+1)

C. 2x^2 (x-y) (x+y)

D. 2x^2y (x-1) (x^2+x+1)

E. 2x^2 (x-y) (x^2+xy+y^2)

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Answers (1)
  1. 18 June, 20:41
    0
    Option D, 2x^2y (x - 1) (x^2 + x + 1)

    Step-by-step explanation:

    Step 1: Factor

    2x^5y - 2x^2y

    2x^2y (x^3 - 1)

    2x^2y (x - 1) (x^2 + x + 1)

    Answer: Option D, 2x^2y (x - 1) (x^2 + x + 1)
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