Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and A2 the event that the right leg tag is lost. Suppose these two events are independent and P (A1) = P (A2) =.4. Find the probability that exactly one tag is lost, given that at least one tag is lost.

Question

Mathematics

Miley Hines

8 July, 00:28

Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and A2 the event that the right leg tag is lost. Suppose these two events are independent and P (A1) = P (A2) =.4. Find the probability that exactly one tag is lost, given that at least one tag is lost.

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Answers (1)

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Mack · Answer 1

Answer: 0.51

Step-by-step explanation:

Since A1 and A2 are independent so

P (A1 and A2) = P (A1) P (A2) = 0.3*0.3 = 0.09

By the addition rule, the probability that at least one leg tag is lost is

P (A1 or A2) = P (A1) + P (A2) - P (A1 and A2) = 0.3+0.3-0.09 = 0.51