Find the function that is finally graphed after the following transformations are applied to the graph of y = square root x

The graph is shifted down 6 units, reflected about the x-axis, and finally shifted left 2 units.

x.

y = - (x+2) ^2 - 6

Step-by-step explanation:

y=a (x-h) ^2 + 6

a=-1

h=-2

k=-6

The vertex of y=x^2 is on (0,0)

When you shift an equation down, and when you shift an equation left you are basically subtracting from the y and x components respectively, so:

(0-2,0-6) = (-2,-6) = (h, k)

Or, you can just remember that a positive k (or y), is above the origin and a negative k is below the origin.

H (or x) is the opposite. Positive h is to the left and negative h is to the right.