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A chemical company makes two brands of antifreeze. The first brand is 40%pure antifreeze, and the second brand is 90%pure antifreeze. In order to obtain 160

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  1. Today, 10:59
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    Complete question:

    A chemical company makes two brands of antifreeze. The first brand is 40% pure antifreeze, and the second brand is 90% pure antifreeze. In order to obtain 160 gallons of a mixture that contains 60% pure antifreeze, how many gallons of each brand of antifreeze must be used?

    Answer:

    Amount of 40% pure antifreeze = y = 96gallons

    Amount of 90% pure antifreeze = ((160-y) = (160 - 96) = 64gallons

    Step-by-step explanation:

    Brand A = 40% pure

    Brand B = 90% pure

    Therefore to obtain 160 gallons that contains 60% pure antibfreeze:

    Let y = Amount of 40% pure antifreeze required

    Therefore (160 - y) = Amount of 90% pure antifreeze required.

    Expressing mathematically,

    0.4y + (160 - y) (0.9) = 160*0.6

    0.4y + 144 - 0.9y = 96

    -0.5y = 96 - 144

    -0.5y = - 48

    y = 48 / 0.5

    y = 96

    Amount of 40% pure antifreeze = y = 96gallons

    Amount of 90% pure antifreeze = ((160-y) = (160 - 96) = 64gallons
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