What equation is the inverse of 2 (x-2) ^2 = 8 (7+y)

- Y=2+√4x+28 -

Step By Step:

Ok so, the original expression is 2 (x - 2) ² = 8 (7 + y).

First you Rewrite the expression as 7 + y = (2/8) * (x-2) ² = (1/4) * (x-2) ²

So know its; y = (1/4) (x-2) ² - 7

To find the inverse, switch x and y, and solve for y.

x = (1/4) (y-2) ² - 7

Then you Multiply through by 4

4x = (y-2) ² - 28

(y-2) ² = 4x + 28

y - 2 = √ (4x + 28)

y = 2 + / - √ (4x + 28)