There are seven competitors in the jured art showcase in how many ways may the judges choose a winner

and a fost runner-up)

Question

Mathematics

Marco Hammond

13 February, 06:58

There are seven competitors in the jured art showcase in how many ways may the judges choose a winner

and a fost runner-up)

+3

Answers (1)

Know the Answer?

Gretta · Answer 1

The number of ways in which the judge can choose the winner and a first runner up = 42

Step-by-step explanation:

Step 1:

Number of competitors in the art show case = 7

We need to find the number of ways the judges can choose the winner and the first runner up.

Step 2:

The number of ways using which the judge can choose the winner = 7

(Since there are 7 competitors)

The number of ways using which the judge can choose the first runner up = 6

(Since the winner is already chosen, the remaining number of competitors will be 7 - 1 = 6)

Hence the number of ways in which the judge can choose the winner and a first runner up = 7 * 6 = 42

Step 3:

Answer:

The number of ways in which the judge can choose the winner and a first runner up = 42

There are seven competitors in the jured art showcase in how many ways may the judges choose a winnerand a fost runner-up)

There are seven competitors in the jured art showcase in how many ways may the judges choose a winner

and a fost runner-up)