Two factory plants are making TV panels. Yesterday, Plant A produced 4000 panels. Six percent of the panels from Plant A and 2% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was3%?

Question

Mathematics

Kaden Graves

30 May, 14:24

Two factory plants are making TV panels. Yesterday, Plant A produced 4000 panels. Six percent of the panels from Plant A and 2% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was3%?

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Answers (1)

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Eliza Foley · Answer 1

12,000 panels are produced by Plant B.

Step-by-step explanation:

Plant A produced 4000 panels. Plant B produced 'x' panels. Total panel produced by both A and B = (4000+x)

The percentage of defective panels,

6% of plant A + 2% of plant B = 3% of both A and B

6/100 (4000) + 2/100 (x) = 3/100 (4000+x)

240 + 0.02x = 120 + 0.03x

240-120 = 0.03x-0.02x

120 = 0.01x

x = 120/0.01

x = 12,000

The plant B produced 12,000 panels.