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6 May, 08:28

Determine the solution that exists to the equation below.

8 (j-4) = 2 (4j-16)

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Answers (2)
  1. 6 May, 09:40
    0
    All Real Numbers Are Solutions

    Explanation:

    8 (j - 4) = 2 (4j - 16)

    [ Simplify both sides of the equation ]

    8 (j - 4) = 2 (4j - 16)

    (8) (j) + (8) (-4) = (2) (4j) + (2) (-16) (Distribute)

    8j + - 32 = 8j + - 32

    8j - 32 = 8j - 32

    [ Subtract 8j from both sides ]

    8j - 32 - 8j = 8j - 32 - 8j

    -32 = - 32

    [ Add 32 to both sides ]

    -32 + 32 = - 32 + 32

    0 = 0

    Therefore, all real numbers are solutions.
  2. 6 May, 09:57
    0
    infinite solutions

    Step-by-step explanation:

    8 (j-4) = 2 (4j-16)

    Distribute

    8j - 32 = 8j - 32

    Subtract 8j from each side

    8j-8j - 32 = 8j-8j - 32

    -32 = - 32

    This is always true so there are infinite solutions
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